3x^2-95x-1000=0

Solution for 3x^2-95x-1000=0 equation:

3x^2-95x-1000=0

a = 3; b = -95; c = -1000;
Δ = b2-4ac
Δ = -952-4·3·(-1000)
Δ = 21025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21025}=145$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-145}{2*3}=\frac{-50}{6}
=-8+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+145}{2*3}=\frac{240}{6}
=40
$